Spaceflight Now has two good photos showing the fairing, which reveal an overall length of about 61 ft: http://www.spaceflightnow.com/titan/b26/051019mst.html That was one of the two scenarios I discussed earlier: http://satobs.org/seesat/Oct-2005/0180.html which I believe indicates a standard KH, but reverting to the type of fairing configuration and length used in the pre-2001 KH launches. Apparently, the fairing on the patch was not to actual scale. So, assuming on-time launch today (2005 Oct 19) at 18:04 UTC, I suggest this search orbit: 175 X 1029 km 1 72001U 05292.79844637 .00807205 00000-0 10000-2 0 04 2 72001 97.8760 354.5813 0611200 101.3444 265.7048 14.87728598 06 The argument of perigee could differ somewhat. If the intention is to match that of the current occupant of the target plane (USA 129 / 96072A / 24680), then the argument of perigee would be 117.3 deg, and the mean anomaly would be 249.7492 deg. Assuming that the above orbit is correct, then South Africa will have passes within a few hours of launch, followed some time later by New Zealand and Australia. Ted Molczan ------------------------------------------------------------------------- Subscribe/Unsubscribe info, Frequently Asked Questions, SeeSat-L archive: http://www.satobs.org/seesat/seesatindex.html
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