> You've the miles and km the wrong way around. > 1 mile = 1.612 km > So 22,300 miles = 35,947.6 km (geostationair) and 60,000 miles = 96720 km MAJOR OOPS! Sorry. But the question still remains. Using the formula: v = 2 pi x (radius of Earth + alt of sat)/period v = 2 x 3.1416 x (3,963 mi + 22,300 mi)/24 hr My spreadsheet tells me at an altitude of 60,000 miles (96720km) a satellite needs to cruise at 16,745 mph (26993kph) to remain geostationary. What would happen to this orbit? Is it possible to remain geostationary out there? I realize it would be very inefficient, but is it possible? Thanks, Bill ----------------------------------------------------------------- Unsubscribe from SeeSat-L by sending a message with 'unsubscribe' in the SUBJECT to SeeSat-L-request@lists.satellite.eu.org http://www.satellite.eu.org/seesat/seesatindex.html
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