Kevin Feter posted his observations and a possible elset. His session was 27 minutes. During this time, the object did not show significant deviation from a nominal geosynchronous orbit. The mean declination was about 0.2 degrees north of a zero inclination orbit. So an orbit with that inclination would be: Unknown 061101 1 99999U 06805A 06305.40339574 0.00000000 00000-0 00000-0 0 06 2 99999 0.2263 308.1612 0001000 318.2253 181.1292 1.00270000 00 There is possibly some deviation from a constant declination during the 27 minutes. So a slightly more inclined orbit is: Unknown 061101 1 99999U 06805A 06305.28149759 0.00000000 00000-0 00000-0 0 06 2 99999 0.3663 264.1612 0001000 318.2253 181.1292 1.00270000 06 It is possible that the inclination could be as high as 0.46: Unknown 061101 1 99999U 06805A 06305.25378926 0.00000000 00000-0 00000-0 0 03 2 99999 0.4663 254.1612 0001000 318.2253 181.1292 1.00270000 06 It is also possible that the mean motion differs slightly from 1.0027. Mike McCants ------------------------------------------------------------------------- Subscribe/Unsubscribe info, Frequently Asked Questions, SeeSat-L archive: http://www.satobs.org/seesat/seesatindex.html
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