Compute the position of the geostationary in your equatorial plane: X=(35790+6370)*COS(dLong)-6370*COS(Lat) Y=(35790+6370)*SIN(dLong) Z=-6370*SIN(Lat) And the distance to the geostationary: D=SQRT(X*X+Y*Y+Z*Z) Then the altitude of the geostationary is Alt = ASIN((X*COS(Lat)+Z*SIN(Lat))/D) With dLong = 101-80.14 = 20.86 and Lat = 42.07 I get Alt = 36.99 degrees You will have Alt>10 for 64.6 degrees, i.e. Long = [-15.52,-144.76] And Alt>0 for Long = [-1.89,-158.39] > Does anyone have a formula (other than star charting software) for > calculating a geosat's apparent altitude given its final parking longitude? > > For instance tonight's DirecTV launch is destined for 101 degrees West. Excel spreadsheet sent to Bill. -- bjorn.gimle@tietotech.se (office) -- -- b_gimle@algonet.se (home) http://www.algonet.se/~b_gimle -- -- COSPAR 5919, MALMA, 59.2576 N, 18.6172 E, 23 m -- -- COSPAR 5918, HAMMARBY, 59.2985 N, 18.1045 E, 44 m -- ----------------------------------------------------------------- Unsubscribe from SeeSat-L by sending a message with 'unsubscribe' in the SUBJECT to SeeSat-L-request@lists.satellite.eu.org http://www.satellite.eu.org/seesat/seesatindex.html
This archive was generated by hypermail 2b29 : Tue Nov 27 2001 - 05:20:13 EST