Scott Campbell asked: > Lacrosse 5 > 1 28646U 05016A 06063.08279891 -.00000020 00000-0 -47410-5 0 05 > 2 28646 57.0078 60.1673 0013305 345.2020 14.8214 14.53345426 03 Apparently so. Using all 10 points reported over a one day arc that ended last night, I obtained the following: Lacrosse 5 15.0 4.0 0.0 2.5 v 1 28646U 05016A 06063.08280542 -.00000078 00000-0 -18589-4 0 07 2 28646 57.0077 60.1673 0012082 348.6097 11.4641 14.53345170 07 Arc 2006 Mar 03.06 - 04.09, WRMS residuals = 0.014 deg I allowed all elements to vary, except for decay, which I retained from my previous solution. Here is another version, this time with inclination fixed at the value of the previous elset: 1 28646U 05016A 06063.08280654 -.00000078 00000-0 -18589-4 0 01 2 28646 57.0134 60.1752 0012472 347.3921 12.6779 14.53345552 03 Arc 2006 Mar 03.06 - 04.09, WRMS residuals = 0.014 deg In both cases, the main changes relative the previous elements, are an apparent increase in mean eccentricity, and a reduction in argument of perigee of nearly 50 deg. In mid-January, it appeared to manoeuvre to increase its argument of perigee by 70 deg, as I reported here: http://satobs.org/seesat/Feb-2006/0082.html Ted Molczan ------------------------------------------------------------------------- Subscribe/Unsubscribe info, Frequently Asked Questions, SeeSat-L archive: http://www.satobs.org/seesat/seesatindex.html
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