Re: I have a problem = looks like me see unid sat :)

From: C. Bassa (cgbsat@gmail.com)
Date: Tue Jun 04 2013 - 21:02:17 UTC

  • Next message: Ed Cannon: "one that got away"

    Kevin kindly provided me with the video of this observation. I also
    reanalized his video from the May 30 pass, as I had not used my latest
    software when reducing it. From both videos I obtain these
    observations:
    99207 13 650A   1775 G 20130530072850393 17 25 1735382-132597 37 I
    99207 13 650A   1775 G 20130530072851510 17 25 1735643-131147 37 I
    99207 13 650A   1775 G 20130530072852626 17 25 1735931-125676 37 I
    99207 13 650A   1775 G 20130530072853560 17 25 1736165-124436 37 I
    99207 13 650A   1775 G 20130604060858998 17 25 1914704+121465 37 S
    99207 13 650A   1775 G 20130604060900999 17 25 1917210+130770 37 S
    99207 13 650A   1775 G 20130604060902999 17 25 1919659+135976 37 S
    
    These observations improve my earlier search orbit to this estimate,
    fitting for all parameters except eccentricity and B* drag:
    1 99207U          13155.25626156  .00000000  00000-0  50000-4 0    07
    2 99207  72.0259 255.5944 0020000 337.6259  66.2618 14.77172709    09
    
    These elements are consistent with those of objects from the 2010-062 launch.
    
    Regards,
        Cees
    _______________________________________________
    Seesat-l mailing list
    http://mailman.satobs.org/mailman/listinfo/seesat-l
    



    This archive was generated by hypermail 2b29 : Tue Jun 04 2013 - 21:03:58 UTC