> > > And a dark satellite of 6*6 m would only remove ~25% of the Moon's > > light > > during 1/600 s. - how long is your camera's exposure time/frame ? > > I base my proposed exposures on the phase of the moon as I am > looking for a silhouette image cast by the satellite against the lunar > surface. I do not want to determine the exposure on the basis of the > satellite as any overexposure of the lunar surface will not only destroy > the esthetics of the image but it may/should destroy the silhouette of > the satellite as well. > My point here is that if you determine the exposure time to be 1/30 second, the satellite will reduce the intensity of a particular pixel only during 1/600. If it covers 25% of the pixel, that is only 1.2% contrast ! It also illustrates the dilemma of satellite photography (with a "stationary" camera) - there is "no" time for a CCD to accumulate photons (except for very wide field, or geostationary satellites) (Film also accumulates photons, but less efficiently on long exposures) ----------------------------------------------------------------- Unsubscribe from SeeSat-L by sending a message with 'unsubscribe' in the SUBJECT to SeeSat-L-request@lists.satellite.eu.org http://www2.satellite.eu.org/seesat/seesatindex.html
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