Re: AURA launch

From: Russell Eberst (eberst@blueyonder.co.uk)
Date: Thu Jul 08 2004 - 06:21:03 EDT

  • Next message: Brian Webb: "Aura Launch"

    At 22:34 08/07/04 +1200, you wrote:
    
    >AURA is due to be launched from Vandenberg on July 11 between 10:01:57 and
    >10:04:57 UTC. Launch vehicle is a Delta 2 rocket.  (Note: some sources give
    >July 10 launch but it seems that is has been postponed for a day "for
    >records check."  Source- Spaceflight Now.)  NASA-TV is showing it scheduled
    >for 11 July.
    >
    >Its orbit is described as "438 mi (705 km) polar, sun-synchronous, 1:45 PM
    >ascending node" and "near polar, sun-synchronous orbit with a period of
    >approximately 100 minutes."
    >
    >Presumably from this information it should be possible to calculate launch
    >track and provisional TLEs?  (I cannot find a launch track on any of the
    >relevant websites.)
    
    Using the following website:
    http://aura.gsfc.nasa.gov/mission/formation_flying.html
    
    we find that Aura follows Aqua by "a nominal 15 minutes". This corresponds to
    about 54 degrees in mean anomaly. So if we take a recent tle for Aqua:
    
    Aqua             8.0  4.0  2.5  4.0 d   18       703 x 702 km
    1 27424U 02022A   04189.39469568  .00000094  00000-0  30835-4 0  7722
    2 27424  98.2218 129.0365 0001165  83.9975 276.1352 14.57108827115793
    
    and deduct 54 degrees from the mean anomaly (276.1352), we get
    
    Aura             8.0  4.0  2.5  4.0 d   18       703 x 702 km
    1 88888U 04000A   04189.39469568  .00000094  00000-0  30835-4 0  7722
    2 88888  98.2218 129.0365 0001165  83.9975 222.1352 14.57108827115793
    
    Remember that "15 minutes" is a nominal figure, so a margin of 5-10 minutes
    should be allowed for this provisional TLE.
    
    
    
    Best wishes,
    Russell  Eberst
    55.9486N,   3.1383W,  150 feet = 46 metres above MSL
    
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