At 13:27 1/07/01 , McConahy, Ralph wrote: > >Just received the following... > >MAP (SATID 0102701; NORAD # 26859) SEPARATION PLUS 6HR. STATE >.... Here is my suggestion for a TLE, based on this information. The argument of perigee,the eccentricity , RA of the node and the inclination are taken directly from the Mean equator of date values. I had to calculate the mean motion I give the unperturbed value. The checksums are not correct. Other values of interest are coded into the data. The perigee height of the current orbit is 182Km, with an apogee height of 296,000Km approx. MAP 1 26859U 01027A 01181.89580000 .00000000 00000-0 +00000-0 0 00112 2 26859 28.7308 034.6199 9570422 048.5164 000.8347 00.14547093800014 Assummimg the drag area corresponds to an average surface area, and ignoring solar panel glints I predict a magnitude around 16 at apogee of current orbit. The corresponding magnitude at the Sun Earth L2 is 19.5 This is rather faint but not beyond the capabalities of those who find/follow asteroids. There are some who have only lx-200 30cm telescopes( and CCD's) who could make observations on such an object. Tony Beresford Adelaide, So. Australia >SPACECRAFT MASS 836.46 KG >SPACECRAFT AREA 20.438 SQUARE METERS >COEFFICIENT OF DRAG 2.2 >COEFFICIENT OF SOLAR RADIATION 1.3 > > >----------------------------------------------------------------- >Unsubscribe from SeeSat-L by sending a message with 'unsubscribe' >in the SUBJECT to SeeSat-L-request@lists.satellite.eu.org >http://www2.satellite.eu.org/seesat/seesatindex.html > ----------------------------------------------------------------- Unsubscribe from SeeSat-L by sending a message with 'unsubscribe' in the SUBJECT to SeeSat-L-request@lists.satellite.eu.org http://www2.satellite.eu.org/seesat/seesatindex.html
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