(fwd) ln(2)+ln(3)+ln(5)+ln(7)+...+ln(p)

Patrick Schmeer (pasc@stud.uni-sb.de)
Thu, 26 Jan 95 14:24:19 +0100

p =             ln(p#) ~=               p-sqrt(p) ~=
------------------------------------------------------------
11              7.745003                7.683375
101             88.343511               90.950124
1009            963.161980              977.235240
10007           9905.202419             9906.965006
100003          99696.902224            99686.767491
1000003         998497.990539           999002.998500
10000019        9995195.435954          9996856.719336
100000007       99987748.438694         99990006.999650
1000000007      999968999.301105        999968384.223288
10000000019     ?                       9999900018.999905

If you want an effective upper bound: ln(p#) < p*ln(4).

Bye,
  Rob.
     .-.                   robert@vlsi.cs.caltech.edu                  .-.
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