> For example, let's say a new satellite is observed at magnitude > +5.0 at precisely 1000-km slant range (to remove range from > the equation), and 75% "illumination", which I take to mean > a sun-satellite-observer angle of 45 degrees. What is this > satellite's standard magnitude? (The correct answer is +5.94). According to the formula A - 15.75 + 2.5 x log (BxB/C), where A = the Standard magnitude, where B = the range in kilometers, and where C = the satellite illumination, If I input 5.94 for A, 1000km for B, and 75% for C, I get +5.50. Conclusions? ------------------------------ Jonathan T. Wojack tlj18@juno.com 39d45'N 75d33'W ________________________________________________________________ GET INTERNET ACCESS FROM JUNO! Juno offers FREE or PREMIUM Internet access for less! Join Juno today! For your FREE software, visit: http://dl.www.juno.com/get/tagj. ----------------------------------------------------------------- Unsubscribe from SeeSat-L by sending a message with 'unsubscribe' in the SUBJECT to SeeSat-L-request@lists.satellite.eu.org http://www2.satellite.eu.org/seesat/seesatindex.html
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