Re: Maximum distance to launch ground tracks

From: Jonathan T Wojack (tlj18@juno.com)
Date: Sun Apr 29 2001 - 14:00:24 PDT

  • Next message: Jonathan T Wojack: "Re: STS-98 trajectory plots"

    > The formula for maximum surface distance on the Earth (in 
    > kilometers) an
    > object at HEIGHT (also in kilometers) can be seen is given by:
    
    At the calculated distance - at what altitude is the object above the
    observer's horizon?
     
    > DIST = 6371 * {arccos[6371/(6371 + HEIGHT)]  /  57.29577}
    
    I'm not familiar with the term "arccos".  How does it differ from the
    mathematical function cosine?
     
    ------------------------------
    Jonathan T. Wojack                 tlj18@juno.com
    39.706d N   75.683d W            
    
    4 hours behind UT (-4)
    
    ________________________________________________________________
    GET INTERNET ACCESS FROM JUNO!
    Juno offers FREE or PREMIUM Internet access for less!
    Join Juno today!  For your FREE software, visit:
    http://dl.www.juno.com/get/tagj.
    
    -----------------------------------------------------------------
    Unsubscribe from SeeSat-L by sending a message with 'unsubscribe'
    in the SUBJECT to SeeSat-L-request@lists.satellite.eu.org
    http://www2.satellite.eu.org/seesat/seesatindex.html
    



    This archive was generated by hypermail 2b29 : Sun Apr 29 2001 - 17:32:59 PDT