Robert Matson wrote: > Mag = Std. mag + 2.5*LOG((1600/1000)^2) -or- > Mag = Std. mag + 5*LOG(1600/1000) > = 5.5 + 1.02 = 6.52 > .... > A simplified general equation for object at 90-degree > phase angle is: > > Mag = Std. mag - 15 + 5*LOG(Range) > > where Range is in km. Jonathan Wojack replied: > I'm just trying to understand the math involved - where does the -15 come > from? Thanks to both of you for this most "illuminating" (sorry) discussion. I think Robert has answered all of the questions except this last one of Jonathan's so I'll venture to point out that 5*LOG(1000) = 15. Subtracting 15 from the multiplied log value is the same as dividing the actual range by the standard range (1000km) before taking the log. Ed. ----------------------------------------------------------------- Unsubscribe from SeeSat-L by sending a message with 'unsubscribe' in the SUBJECT to SeeSat-L-request@lists.satellite.eu.org http://www2.satellite.eu.org/seesat/seesatindex.html
This archive was generated by hypermail 2b29 : Thu Apr 26 2001 - 15:26:50 PDT